solve the question given over
prove that question
Attachments:
Answers
Answered by
5
SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT
#TOGETHER WE GO FAR✔✔
Attachments:
Answered by
4
Answer:
If a², b², c² are in A.P and (b+c),(c+a),(a+b) ,are in H.
THEN,
a²+c²=2b↔(1/a+b) +1/(b+c)=2/(c+a)
Now,
(a+c+2b)/(a+b)(b+c)=2/(a+c)
{(a+c)+2b}(a+c)=2(a+b)(b+c)
(a+c)²+2b(a+c)=2(ba+bc)+2(b²+ac)
(a+c)²=2(b²+ac)
a²+c²+2ac=2b²+2ac
a²+c²=2b²
Similar questions