Math, asked by kssbebb, 1 year ago

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Answered by Anonymous
5

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

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Answered by Anonymous
4

Answer:

If a², b², c² are in A.P and (b+c),(c+a),(a+b) ,are in H.

THEN,

a²+c²=2b↔(1/a+b) +1/(b+c)=2/(c+a)

Now,

(a+c+2b)/(a+b)(b+c)=2/(a+c)

{(a+c)+2b}(a+c)=2(a+b)(b+c)

(a+c)²+2b(a+c)=2(ba+bc)+2(b²+ac)

(a+c)²=2(b²+ac)

a²+c²+2ac=2b²+2ac

a²+c²=2b²

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