Question

solve the question immediately urgently solution required

Answer 1

Heat conduction flow rate..

   Heat flowing (conduction) between the ends of a rod is proportional to the area of cross section A, thermal conductivity k, of the material of rod and inversely proportional to the length of the rod.  Heat is proportional to the difference between the temperatures of the two ends.

   Here three identical rods are arranged in an equilateral triangle. Let the temperature at junction B be equal to T deg C.

Heat flow rate from A to C = k A/L * (100° - 50°) = 50 k A / L
Heat flow rate from A to B = k A/L * (100° - T)
Heat flow rate from C to B = k A / L * (T - 50°)
  
1) If heat flowing in AC = heat flowing in AB, then T = 50°
     => Assuming their conductivities are equal.

2) if heat flowing in AC = heat flowing in BC , then 
     => kA/L * (100° - T) = k A / L * (T - 50°)
     => 100 - T = T - 50
     => 2 T = 150°
     => T = 75°

Answer 2

the heat flow in a conductor is directly proportional to :-

square of current

resistance of conductor

timr