solve the question no 12
Attachments:
Answers
Answered by
0
Hey
Here is your answer,
Let the fraction be x/y.
Given that ,
The denominator of a fraction is 1 less than four times the numerator.
y = 4x - 1
4x-y=1
Multiply by 2,
8x - 2y =2
__________ Equation 1
x+1/y+1 = 3/8
8(x+1)=3(y+1)
8x + 8 = 3y + 3
8x - 3y = 3-8
8x - 3y = -5
__________ Equation 2
Solving both the equations by elimination method,
8x - 2y = 2
8x - 3y = -5
________
y = 7
y=4x-1
4x=y+1
4x=7+1
4x=8
X = 8/4
X = 2
The fraction is 2/7.
Hope it helps you!
Here is your answer,
Let the fraction be x/y.
Given that ,
The denominator of a fraction is 1 less than four times the numerator.
y = 4x - 1
4x-y=1
Multiply by 2,
8x - 2y =2
__________ Equation 1
x+1/y+1 = 3/8
8(x+1)=3(y+1)
8x + 8 = 3y + 3
8x - 3y = 3-8
8x - 3y = -5
__________ Equation 2
Solving both the equations by elimination method,
8x - 2y = 2
8x - 3y = -5
________
y = 7
y=4x-1
4x=y+1
4x=7+1
4x=8
X = 8/4
X = 2
The fraction is 2/7.
Hope it helps you!
Answered by
0
Let the numerator be X and denominator be
X/ 4(X)-1 as they said in the question. Then adding 1 in denominator and numerator.
.
.
.
.
.
X/ 4(X)-1 as they said in the question. Then adding 1 in denominator and numerator.
.
.
.
.
.
Similar questions