Question

Solve the question number 39 for me factories

Answer 1

Answer:

500

Step-by-step explanation:

Answer 2

Answer:

500

Step-by-step explanation:

Let $A=361$.

And let $B=139$.

Simplify : $\frac{A^3+B^3}{A^2-AB+B^2}$

We know that $A^3+B^3=(A+B)(A^2-AB+B^2)$.

From that, $\frac{A^3+B^3}{A^2-AB+B^2}=A+B$ (Where $A^2-AB+B^2\neq 0$)

Also, we know that $A^2-AB+B^2\neq 0$.

Hence, $\frac{A^3+B^3}{A^2-AB+B^2}=361+139=500$.

The answer is 500.