Question

solve the question please

Answer 1

Answer:

Step-by-step explanation:

L.H.S =(√1+cosθ/√1-cosθ)+(√1-cosθ/√1+cosθ)

multiply above with their inverse

• [(√1+cosθ/√1-cosθ)*(√1+cosθ/√1+cosθ)]+[(√1-cosθ/√1+cosθ)*(√1-cosθ/√1-cosθ)]

after multiplycation above equation become

• [(√1+cosθ)²/(√1-cos²θ)]+[(√1-cosθ)²/(√1-cos²θ)]

• [(1+cosθ)/√sin²θ]+[(1-cosθ)/√sin²θ]      ///// 1-cos²θ=sin²θ

• [(1+cosθ)/sinθ]+[(1-cosθ)/sinθ]

taking L.C.M

• [(1+cosθ+1-cosθ)/sinθ]

• 2/sinθ

• 2cosecθ=R.H.S