Math, asked by king717, 1 year ago

solve the question please

 \frac{1}{2}  +  \frac{2}{4}  +  \frac{4}{8 }  +  \frac{8}{16}  +  \frac{9}{18}

Answers

Answered by Anonymous
5

Answer:

 \frac{5}{2}  = 2.5

Step-by-step explanation:

\frac{1}{2} + \frac{2}{4} + \frac{4}{8 } + \frac{8}{16} + \frac{9}{18} \\  =  \frac{1}{2}  +  \frac{1}{2}  +  \frac{1}{2 }  +  \frac{1}{2}  +  \frac{1}{2}  \\  =  \frac{1 + 1 + 1 + 1 +  1}{2}  \\  =    \frac{5}{2}  \\  = 2.5

Answered by AbhijithPrakash
10

Answer:

\dfrac{1}{2}+\dfrac{2}{4}+\dfrac{4}{8}+\dfrac{8}{16}+\dfrac{9}{18}=\dfrac{5}{2}\quad \left(\mathrm{Decimal:\quad }\:2.5\right)

Step-by-step explanation:

\dfrac{1}{2}+\dfrac{2}{4}+\dfrac{4}{8}+\dfrac{8}{16}+\dfrac{9}{18}

\black{\dfrac{2}{4}}

\gray{\mathrm{Cancel\:the\:common\:factor:}\:2}

=\dfrac{1}{2}

\black{\dfrac{4}{8}}

\gray{\mathrm{Cancel\:the\:common\:factor:}\:4}

=\dfrac{1}{2}

\black{\dfrac{8}{16}}

\gray{\mathrm{Cancel\:the\:common\:factor:}\:8}

=\dfrac{1}{2}

\black{\dfrac{9}{18}}

\gray{\mathrm{Cancel\:the\:common\:factor:}\:9}

=\dfrac{1}{2}

=\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}

\gray{\mathrm{Apply\:rule}\:\dfrac{a}{c}\pm \dfrac{b}{c}=\dfrac{a\pm \:b}{c}}

=\dfrac{1+1+1+1+1}{2}

\gray{\mathrm{Add\:the\:numbers:}\:1+1+1+1+1=5}

=\dfrac{5}{2}

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