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Option b -10 J
Step-by-step explanation:
dQ (total heat given)=6J
dU (total energy)= 0 [ As it is a cyclic process ]
dW (total work done)= W ab= 18, W bc= 0, Wca= ?
1st law of thermodynamics
dQ= dU+dW
6J=0+18J+0+W ca [ putting the values ]
W ca= (18-6) J = -12J (approx.)
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