solve the question which is in the red line box
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6. Let,the three consecutive nos. are 7x,7x+7, 7x+14.
According to the Question,
7x+7x+7+7x+14=777
21x+21=777
21x=777-21
x=756/21
x=36
Therefore,the three consecutive nos. are 7×36,7×36+7 7×36+14=252,259,266.
7.Let three consecutive nos. are 9x,9x+9,9x+18
According to the Question,
9x+9x+9+9x+18=999
27x+27=999
27x=999-27
x=972/27
x=36
Therefore, the three consecutive nos. are 9×36,9×36+9,9×36+18=324,333,342.
HOPE THE ANSWER WILL HELP YOU.
According to the Question,
7x+7x+7+7x+14=777
21x+21=777
21x=777-21
x=756/21
x=36
Therefore,the three consecutive nos. are 7×36,7×36+7 7×36+14=252,259,266.
7.Let three consecutive nos. are 9x,9x+9,9x+18
According to the Question,
9x+9x+9+9x+18=999
27x+27=999
27x=999-27
x=972/27
x=36
Therefore, the three consecutive nos. are 9×36,9×36+9,9×36+18=324,333,342.
HOPE THE ANSWER WILL HELP YOU.
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