Question

solve the question with full solution

Answer 1

Heya.......!!!!

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This question can be easily sopved by applying " Bernoulli's Theoram " .


----• Given in the question :-

• speed at upper surface ( v2 ) = 120 m/s
• speed at lower surface ( v1 ) = 90 m/s

• Density of air ( d ) = 1.3 kg/m^3

• Length of wing = 10 m
• width of wing = 2 m

We have to first find out the Pressure difference => P1 - P2


◆ According to the Bernoulli 's Equation for a Horizontal plane ,, we have :

=>> P1 + 1/2×d×v1 ²  = P2 + 1/2×d×v2 ² 

i.e => ➡ P1 - P2 = 1/2 × d × ( v2 ² - v1 ² )

= Putting the values ,, we get :-

P1 - P2 = 1/2 × 1.3 × ( 120 ²  - 90 ² )


♦➡Pressure Difference = 4.1 ×10^3 N/m ² 



Now second we have to find out Gross Lift .

We know that Gross Lift = ∆P × A

♦ Gross Lift = 4.1 × 10^3 × 10×2

•➡=>> 8.2 × 10^4 N .


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Hope It Helps You ^_^