solve the rocket one
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Hii friend,
Total height of the rocket = 26 cm
Heigh of the conical part of the rocket (h)= 6 cm
Diameter of the conical part of the rocket = 5 cm.
Radius(R) = D/2 = 5/2 cm
Slant Height (L) = ✓(r)² + (h)² = ✓(5/2)² + (6)² = ✓25/4 + 36 cm = ✓169/4) = 13/2 cm
Diameter of the cylindrical part = 3 cm
Radius of the cylindrical part (r)= D/2 = 3/2 cm
HEIGHT of the cylindrical part of the rocket (H) = Total heigh of the rocket - Height of the conical part of the rocket = 26-6 = 20 cm.
Area of the conical part which is coloured by Green color = CSA of the conical part + Base of the cone - base area of the cylinder.
=> πrl + πr² - πR² = π(rL+r²-R²)
=> [ 3.14 × (5/2 × 13/2 + 5/2 - 3/2 × 3/2)] cm².
=> [ 3.14 × (65/4 + 25/4 -9/4)] cm²
=> [ 3.14 × (65+25-9/4)]
=> (3.14 × 81/4) => (3.14 × 20.25) cm²
=> 63.585 cm².
Area to be painted with red color = CSA of the cylindrical part + Base area of the bottom of the cylinder
=> 2πRH + πR² => πR(2H+R)
=> [ 3.14 × 3/2 ( 2 × 20 + 3/2)] cm²
=> (3.14 × 3/2 × 83/2) cm²
=> (781.86/4) => 195.465 cm².
VOLUME OF THE ROCKET = VOLUME OF CONE + VOLUME OF CYLINDER
=> 1/3πr²h + πR²H
=> π(1/3r²h + R²H)
=> 3.14× (1/3 × 5/2 × 5/2 × 6 + 3/2 × 3/2 × 20)
=> 3.14 × (150/12 + 180/4)
=> 3.14 × (150+540/12)
=> 3.14 × 690/12
=> 2166.6/12
=> 180.55 cm³.
HOPE IT WILL HELP YOU...... :-)
Total height of the rocket = 26 cm
Heigh of the conical part of the rocket (h)= 6 cm
Diameter of the conical part of the rocket = 5 cm.
Radius(R) = D/2 = 5/2 cm
Slant Height (L) = ✓(r)² + (h)² = ✓(5/2)² + (6)² = ✓25/4 + 36 cm = ✓169/4) = 13/2 cm
Diameter of the cylindrical part = 3 cm
Radius of the cylindrical part (r)= D/2 = 3/2 cm
HEIGHT of the cylindrical part of the rocket (H) = Total heigh of the rocket - Height of the conical part of the rocket = 26-6 = 20 cm.
Area of the conical part which is coloured by Green color = CSA of the conical part + Base of the cone - base area of the cylinder.
=> πrl + πr² - πR² = π(rL+r²-R²)
=> [ 3.14 × (5/2 × 13/2 + 5/2 - 3/2 × 3/2)] cm².
=> [ 3.14 × (65/4 + 25/4 -9/4)] cm²
=> [ 3.14 × (65+25-9/4)]
=> (3.14 × 81/4) => (3.14 × 20.25) cm²
=> 63.585 cm².
Area to be painted with red color = CSA of the cylindrical part + Base area of the bottom of the cylinder
=> 2πRH + πR² => πR(2H+R)
=> [ 3.14 × 3/2 ( 2 × 20 + 3/2)] cm²
=> (3.14 × 3/2 × 83/2) cm²
=> (781.86/4) => 195.465 cm².
VOLUME OF THE ROCKET = VOLUME OF CONE + VOLUME OF CYLINDER
=> 1/3πr²h + πR²H
=> π(1/3r²h + R²H)
=> 3.14× (1/3 × 5/2 × 5/2 × 6 + 3/2 × 3/2 × 20)
=> 3.14 × (150/12 + 180/4)
=> 3.14 × (150+540/12)
=> 3.14 × 690/12
=> 2166.6/12
=> 180.55 cm³.
HOPE IT WILL HELP YOU...... :-)
nazzy373:
thanks alot
you answer is wrong please check it 3/2 × 3/2 × 20 = 180/4 not 120/4 first check your answer and then tell to another
Answered by
0
Total height of rocket = 26 cm
height of cone = h = 6 cm
then,
height of cylinder = h¹
= height of rocket - height of cone
= 26 cm - 6 cm
= 20 cm
radius of cone = r1 = 5/2 cm = 2.5 cm
radius of cylinder = r = 3/2 cm = 1.5 cm
1) volume of rocket toy
= volume of cylinder + volume of cone
= πr²h¹ + 1/3 πr1²h
= π(r²h¹+1/3 r1²h)
= π((1.5)²(20) + 1/3(2.5)²(6)
= 3.14(45 + 12.5)
= 3.14(57.5)
= 180.55 cm³
// first find the slant height of cone //
applying Pythagoras thereom
l² = r1² + h²
l² = (2.5)²+(6)²
l² = 42.25
l = √42.25
l = 6.5 cm
2) area of the rocket
= surface area of cylinder + surface area of cone
= 2πrh + πr1l
= π(2rh + r1l)
= π(2×1.5×20 + 2.5×6.5)
= 3.14(60 + 16.25)
= 3.14(76.25)
= 239.425
≈ 239.43 cm²
we also paint the base of cone instead of cylinder upper base,
so area of remain place
= area of circle of the cone - area of the circle of cylinder upper base
= πr1² - πr²
= π(r1² - r²)
= π((2.5)²-(1.5)²
= π(4)
= 3.14(4)
= 12.56 cm²
area of the surface which we painted is
= 239.43 + 12 .56
= 251.99 cm²
height of cone = h = 6 cm
then,
height of cylinder = h¹
= height of rocket - height of cone
= 26 cm - 6 cm
= 20 cm
radius of cone = r1 = 5/2 cm = 2.5 cm
radius of cylinder = r = 3/2 cm = 1.5 cm
1) volume of rocket toy
= volume of cylinder + volume of cone
= πr²h¹ + 1/3 πr1²h
= π(r²h¹+1/3 r1²h)
= π((1.5)²(20) + 1/3(2.5)²(6)
= 3.14(45 + 12.5)
= 3.14(57.5)
= 180.55 cm³
// first find the slant height of cone //
applying Pythagoras thereom
l² = r1² + h²
l² = (2.5)²+(6)²
l² = 42.25
l = √42.25
l = 6.5 cm
2) area of the rocket
= surface area of cylinder + surface area of cone
= 2πrh + πr1l
= π(2rh + r1l)
= π(2×1.5×20 + 2.5×6.5)
= 3.14(60 + 16.25)
= 3.14(76.25)
= 239.425
≈ 239.43 cm²
we also paint the base of cone instead of cylinder upper base,
so area of remain place
= area of circle of the cone - area of the circle of cylinder upper base
= πr1² - πr²
= π(r1² - r²)
= π((2.5)²-(1.5)²
= π(4)
= 3.14(4)
= 12.56 cm²
area of the surface which we painted is
= 239.43 + 12 .56
= 251.99 cm²
no
my answer is right why yiy reported bro
*yu
**yo
*you
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