Solve the second part of q. 16
Please solve it for me
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ATQ :
7(a7) = 11(a11)
=> 7 (a + 6d) = 11 ( a + 10d)
=> 7a + 42d = 11a +110d
=> -4a = 68d
=> a = -17d
=> -a = 17d -----------(1)
a18 = a + 17d ( from 1)
=> a18 = a + (-a)
=> a18 = 0
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