solve the simultaneous eqn :
x + 2y + 9 = 0
3x + 4y + 17 = 0
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x + 2y = - 9 ... (1)
3x + 4y = - 17 ... (2)
Multiply (1) by 3:
→ 3(x + 2y) = (-9)3
→ 3x + 6y = - 27 ... (3)
(3) - (2):
→ (3x + 6y) - (3x + 4y) = - 27 - (-17)
→ 2y = - 27 + 17 = - 10
→ y = (-10/2) = - 5
Putting the value of y in 1equation,
x + 2(-5) = -9
x = 10 - 9 = 1
Therefore, x = 1 & y = - 5
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