solve the simultaneous equation . 3x+y=10 , x-y=2
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3x+y=10 .... equation 1
x-y=2 .... equation 2
add equation 1 and 2
3x+y=10
+ x-y=2
= 4x =12 (+y and -y will get cancelled)
= x =12/4
= x=3
substitute the value of x in equation 1
= 3x+y=10
= 3(3)+y=10
= 9+y=10
= y=10-9
= y=1
Therefore (x,y) is (3,1) is the solution of the given equation.
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