Question

solve the simultaneous equations:
1.32u-33v=97 ; 33u-32v=96
​

Answer 1

Answer:

eqn 1 : 1.32u-33v=97

eqn  2 : 33u-32v=96

by subtracting eqn 2 from eqn 1, we get

(1.32u-33u) + (-33v +32v) =97-96

31.68u -1v =1

∴ v= 31.68u-1  

substituting the value of v in eqn 2, we get

33u -32(31.68u-1) = 96

33u-1013.76u + 32 = 96

-980.76u = 64

∴ u=-0.06525≈0.0653

v=31.68u-1

 = 31.68×0.06525 -1

 =  1.06712 ≈ 1.067

∴ u=0.0653 ; v=1.067

The method I used here is substitution method

Hope it helps you :)