Question

solve the simultaneous linear eq (std 10) no spam❌❌​

Answer 1

GIVEN :-

$\sf \: 4x + \frac{y}{3} = \frac{8}{3} \: \: \: \: \: \: \: ... (i) \\ \\ \sf \: \frac{x}{2} + \frac{3y}{4} = - \frac{5}{2} \: ...(ii)$

SOLUTION :-

$\sf \: 4x + \frac{y}{3} = \frac{8}{3 }$

$\implies\sf \: \frac{12x + y}{3} = \frac{8}{3}$

$\sf \implies \: 12x + y = 8$

$\sf \implies \: y = 8 - 12x \: \: \: \: \: \: \: \: ...(iii)$

$\sf \star \: Putting \: \: in \: \: equation \: \: (ii)$

$\sf \frac{x}{2} + \frac{3y}{4} = - \frac{5}{2}$

$\implies \sf \frac{x}{2} + \frac{3(8 - 12x)}{4} = - \frac{5}{2}$

$\implies \sf \frac{x}{2} + \frac{3 \times 4(2 - 3x)}{4} = - \frac{5}{2}$

$\implies \sf \frac{x}{2} + 3(2 - 3x) = - \frac{5}{2}$

$\implies \sf \frac{x}{2} +6 - 9x= - \frac{5}{2}$

$\implies \sf \frac{x}{2} - 9x= - \frac{5}{2} - 6$

$\implies \sf \frac{x - 18x}{2} = \frac{ - 5 - 12}{2}$

$\implies \sf \frac{ - 17x}{2} = \frac{ - 17}{2}$

$\green{ \boxed{ \sf \implies \: x = 1}}$

$\sf \: Putting \: the \: value \: of \: x \: in \: eq \: (iii)$

$\sf \implies \: y = 8 - 12(1)$

$\sf \implies \: y = 8 - 12$

$\sf \implies \: y = - 4$

$\green{ \boxed{ \sf \implies \: y= - 4}}$

Answer 2

Answer:

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