Question

Solve the simultaneous linear equations by the elimination method.

x + 1

2

+

y − 1

3

= 8

x − 1

3

+

y + 1

2

= 9​

Answer 1

Answer:

How do you solve the equation x/2 + y/3 =1 x/3 +y/2 =1 by elimination method?

New Study: Discover the secrets to CRM success.

Murali Krishna

Answered June 9, 2020

X/2+y/3 =1

x/3 +y/2 =1

By taking LC M

3x+2y= 6 (3)

2x+3y=6 (4)

Eqalise coefficient of x

(3) ×2= 6x+4 y= 12

(4) ×3= 6x+9y= 18

Subtracting

--5y= — 6

y=6/5

2x+3×6/5 =6

2x= 6-- 18/5 = 12/5

x= 12/5 ×1/2= 6/5

values of x=6/5 and. y=6/5

Verification

3×6/5+ 2×6/5 =30/5 =6

2×6/5+3×6/5 =30/5=6