solve The sum of a number and its reciprocal is 13/6. find the number .
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x + 1/x = 13/6
(x2+1)/x = 13/6
x2+1 = 13x/6
x2 = (13x -6)/6
6x2 = 13x - 6
6x2-13x+6 = 0
6x2-4x-9x+6 = 0
2x(3x-2)-3(3x-2) = 0
2x-3 = 0 and 3x-2 = 0
x = 3/2 or 2/3
(x2+1)/x = 13/6
x2+1 = 13x/6
x2 = (13x -6)/6
6x2 = 13x - 6
6x2-13x+6 = 0
6x2-4x-9x+6 = 0
2x(3x-2)-3(3x-2) = 0
2x-3 = 0 and 3x-2 = 0
x = 3/2 or 2/3
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