solve the sum solve the sum
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x^2 - 2 + 1/x^2 -1
(x - 1/x ) ^2 - 1
(x - 1/x +1) (x - 1/x - 1)
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5
f(×)=x2+1/x2-3
= x4+1-3x2/x2
Let f(x)=0
=x4-3x2+1=0
=x2(x2-3)+1=0
=x2-2=0
=x2-(√2)2=0
=(x-√2) (x+√2)=0
=x=+√2 or -√2
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