Solve the sum:-
What is its units digit ?
1^5 + 2^5 + 3^5 .......... 99^5
Answers
Answered by
4
Power of 1^5 = 1. Hence Units digit = 1.
Power of 2^5 = 32 - Hence units digit = 2.
Power of 3^5 = 243 - Hence units digit = 3.
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Therefore:
Sum = 99(99 + 1)/2
= 4950
Hope this helps!
Power of 2^5 = 32 - Hence units digit = 2.
Power of 3^5 = 243 - Hence units digit = 3.
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.
Therefore:
Sum = 99(99 + 1)/2
= 4950
Hope this helps!
siddhartharao77:
:-)
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2
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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