Question

Solve the sums along with complete workout.​

Answer 1

Answer:

a centre in the square divides the diagonal into two equal halves so there fore PA+PC =AC and PB+ PD= BD . here in a square all sides are equal then we can write then here AC+ BD > 2AB Hence it's proved

Answer 2

Step-by-step explanation:

64) P is any point inside the square

so now take PAB triangle and PCD triangle

now in any triangle sum of the two sides is greater than third so

in triangle PAB

PA+PB>AB---EQ1

in triangle PCD

PC+PD>CD--EQ2

add eq1 and eq2

PA+PB+PC+PD>AB+CD

in square all sides are equal

so AB=CD

so PA+PB+PC+PD>2AB

hence proved

65)

draw the diagonals of the rectangle

and we know that diagonals of rectangles are equal

so

the point of intersection of diagonals is will be the center of the circle

and circle will pass through all the vertices as well