Question

solve the system of equations 2x+y=7 and 4x-3y+1=0 by substitution method

Answer 1

Answer :

The two given equations are

2x + y = 7

=> y = 7 - 2x ...(i)

4x - 3y + 1 = 0 ...(ii)

Now, substituting the value of y, y = 7 - 2x from (i), in (ii), we get

4x - 3 (7 - 2x) + 1 = 0

=> 4x - 21 + 6x + 1 = 0

=> 10x = 20

=> x = 2

Putting x = 2 in (i), we get

y = 7 - 2 (2) = 7 - 4 = 3

Therefore, the required solution be

x = 2 and y = 3

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Answer 2

⭐⭐Hello friend...Ur answer is here⤵⤵

⚫ 2x+y=7 and 4x-3y= -1

➡ 2x+y=7

➡ y=7-2x

Substitute the value of y

4x-3 (7-2x)= -1

➡ 4x-21+6x= -1

➡ 10x=20

➡ x=2

put the value of x in 2x+y=7

2×2+y=7

➡ y=3

So x=2 and y=3 is the required solution of that system of equation.

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