solve the system using elimination 3x+y=27 -3x+4y=-42
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Given,
3x+y=27 - - - (i)
-3x+4y=-42 - - - (ii)
(i) + (ii) --->
3x+y-3x+4y=27-42
5y= -15
y= - 3
Putting the value of y in (i), we get
3x-3=27
3x=30
x=10
Therefore, x=10 and y= -3
3x+y=27 - - - (i)
-3x+4y=-42 - - - (ii)
(i) + (ii) --->
3x+y-3x+4y=27-42
5y= -15
y= - 3
Putting the value of y in (i), we get
3x-3=27
3x=30
x=10
Therefore, x=10 and y= -3
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