Question

solve the system x+y+z=a;x+y+v=b;z+z+v=c;y+z +v=d.​

Answer 1

Answer:

If a^x=b, b^y=c, c^z=a, what is xyz?

ax=b → (i)

by=c → (ii)

cz=a → (iii)

Using (i) and (ii), we can write

axy=c → (iv)

Using (iii) and (iv), we get

axyz=a1 [Since, a1=a]

or, xyz=1 [Since the bases are equal, the powers will be equal as well]

Hope it helps! :)