solve the trigonometric expressions...
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a) y = 2 sin⁻¹ 3x
then, y = 2 × 1/sin 3x
3x=y sin / 2
x=y sin / 6
b) y = 3 cos⁻¹ 2x
then,y = 3 × 1/cos 2x
2x=y cos / 3
x=y cos / 6
c) y = 1/2 tan⁻¹(x+π)
then, y = 1/2 1/tan (x+π)
x+π=2y tan
x=2y tan / π
:) Hope this helps!!!!!!
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thankz a lot!
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