Math, asked by natashaagrawal, 1 year ago

solve the world problem ....urgent... with solution...

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Answers

Answered by rapidgt
0
total weight of rice=461/6+128/3=717/6
rice remaining=717/6-5/7=5019-30/56=4989/42=1663/14
Answered by Thatsomeone
0
Hey user

Here is your answer :-

the \: first \: bags \: weight \: =76 \times \frac{5}{6}
 <br /><br />= \frac{76 \times 6 + 5}{6}

 = \frac{461}{6} kg

the \: second \: bags \: weight \:= 42 \times \frac{2}{3}
 <br /><br />= \frac{42 \times 3 + 2}{3}
 <br /><br />= \frac{128}{3}
 <br /><br />= \frac{256}{6} kg

total \: weight \: of \: rice \: = \frac{461}{6} + \frac{256}{6} \\ \\ = \frac{461 + 256}{6} \\ \\ = \frac{717}{6} kg

out \: of \: which \: \frac{5}{7} is \: sold


remaining \: rice \: = \frac{717}{6} \times \frac{5}{7} \\ \\ <br /><br />= \frac{3585}{42} kg


Thank you .
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