solve these please: ?
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Answered by
6
Answer:
Heya ✌️
Step-by-step explanation:
✏️(m-n)tan(A+B)
= (m-n) (tanA+tanB)/(1-tanAtanB)
= (mtanA - ntanB)/(1-tanAtanB)
now multiply top and bottom by cosAcosB:
= (msinAcosB-nsinBcosA)/(cosAcosB-sinAsinB)
the rest should follow without difficulty...
2nd one dorakala....
✒️Hope it works ☺️✌️...
Answered by
1
Answer:
(m-n) tan( A +B)
=(m-n)(tan A+tanB)/(1-tanAtanB)
=(mtanA-ntanB)/(1-tanAtanB)
multiply top and bottom by cos Acid B
=(m sin A cos B-n sin BcosA)/
(cosAcosB-sinAsinB)
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