Solve these (please help )
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- 2x + 3y = 0 ........(1)
- (a-b) x + (a+b)y - (3a+b-2) = 0
Or,
- (a-b) x + (a+b)y = (3a+b-2) .....(2)
- Value of x
Firstly,
- 2(a-b)x + 3(a-b)y = 0
- 2(a-b)x + 6(a+b)y = 2(3a+b-2)
_______________Subtract this,
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Take L.H.S.,
=R.H.S.
That's proved
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