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1) Inversely, time
2) For an ideal gas , Cp - Cv = R
3) At 27°c , E = 3/2RT = 3/2 × 2 * 300 = 900 cal.
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
1) Inversely, time
2) For an ideal gas , Cp - Cv = R
3) At 27°c , E = 3/2RT = 3/2 × 2 * 300 = 900 cal.
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
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Heya mate
The answer is here
1) The rate of diffusion of gas is INVERSELY proportional to both TIME and square root of molecular mass .
2 ) Cp - Cv(ratio of specific heats ) for an ideal gas is R .
3 ) The total energy of one mole of an ideal monoatomic gas at 27°C is 900 cal
For 3
E = 3 / 2 × 3 × 300
E = 900 cal
hope it helps
The answer is here
1) The rate of diffusion of gas is INVERSELY proportional to both TIME and square root of molecular mass .
2 ) Cp - Cv(ratio of specific heats ) for an ideal gas is R .
3 ) The total energy of one mole of an ideal monoatomic gas at 27°C is 900 cal
For 3
E = 3 / 2 × 3 × 300
E = 900 cal
hope it helps
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