solve these questions in step by step
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sanjaykumar23:
the answer is easy1:
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(iii) ∠BOC = 180°- ∠AOC ( linear pair)
= 180°-50°
= 130°
(ii)∠ AOD = 180° - ∠AOC
= 180° -50°
=130°
(i) ∠BOD= 50° (OPPOSITE ANGLES)
I guess its like this.... hope it helps...:)
= 180°-50°
= 130°
(ii)∠ AOD = 180° - ∠AOC
= 180° -50°
=130°
(i) ∠BOD= 50° (OPPOSITE ANGLES)
I guess its like this.... hope it helps...:)
Answered by
0
<BOD=50°(opposite angles)
<AOD=130°(linear pair)[180°-50°]
<BOC=130°=AOD(linear pair)
<AOD=130°(linear pair)[180°-50°]
<BOC=130°=AOD(linear pair)
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