Question

solve these. solve. solve. ​

Answer 1

$\huge\underline\bold{Answer:-}$

$1) \: \frac{x + 2}{3} = \frac{3x + 1}{4}$

$= > 4(x + 2) = 3(3x + 1) \\ = > 4x + 8 = 9x + 1 \\ = > 5x = 7 \\ = > x = \frac{7}{5}$

$2) \: \frac{x}{2} + 1 = 5 \\ = > \frac{x + 2}{2} = 5 \\ = > x + 2 = 10 \\ = > x = 8$

$3) \: \frac{x - 2}{3} - \frac{x - 1}{4} = 1 \\ = > \frac{4(x - 2) - 3(x - 1)}{12} = 1 \\ = > \frac{4x - 8 - 3x + 3}{12} = 1 \\ = > \frac{x - 5}{12} = 1 \\ = > x - 5 = 12 \\ = > x = 7$