Math, asked by qwerty94, 1 year ago

Solve these sum
Arjun is twice as old as Shriya five years ago his age was three times Shriya,s age find their present ages

Answers

Answered by BrainlyPrincess
4
Hi friend!!

Let Arjun's present age be x

And Shriya's present age be y

Arjun is twice as old as shriya:-

x = 2y

Their ages before 5 years:-

Arjun's age = x-5

Shriya's age = y-5

Five years ago , his age was three times shriya's age

x-5 = 3(y-5)

x-5 = 3y-15

x-3y = -15+5

2y-3y = -10

-y = -10

y = 10

Therefore,x = 2(10) = 20

The present age of Arjun is 20 years and present age of Shreya is 10 years.

Hope it helps.... Plz mark me as brainliest if my answer helped.

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qwerty94: Wrong
Answered by BrainlySamaira
7

solution:

\footnotesize\texttt{Let us take shriya's age be x years. }

\footnotesize\texttt{then arjun's present age would be 2x years.}

\footnotesize\texttt{shriya's age five years ago was (x-5) years. }

\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }

\footnotesize\texttt{it is given that arjun's age five.}

\footnotesize\textsf{ year ago was three times shriya's age.}

Thus,

\small\mathtt{2x-5=3(x-5) }

\small\mathtt{2x-5=3x-15 }

\small\mathtt{15-5=3x-2x }

\small\mathtt{10= x }

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.

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