solve thia sum of circles
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GIVEN :
ABCD is a cyclic quadrilateral
EC is the tangent to the circle
angle ABC=93°
angle DCE=35°
TO FIND :
angle ADC=?
angle CAD=?
angle ACD=?
SOLUTION :
as ABCD is a cyclic quadrilateral
by the property that opposite angles angles are supplementary
angle ABC + angle ADC=180
so 93 + angle ADC=180
angle ADC=180-93
angle ADC=87°
now,
as EC is a tangent and CD is a chord
by tangent chord theorem
angle DCE=angle CAD
so angle CAD=35°
now,
in triangle ACD
by angle sum property
angle CDA+angle ADC +angle ACD=180
so angle ACD+35+87=180
angle ACD=180-122
angle ACD=58°
so the measures of required angles are
angle ADC=87°
angle CAD=35°
angle ACD=58°
ABCD is a cyclic quadrilateral
EC is the tangent to the circle
angle ABC=93°
angle DCE=35°
TO FIND :
angle ADC=?
angle CAD=?
angle ACD=?
SOLUTION :
as ABCD is a cyclic quadrilateral
by the property that opposite angles angles are supplementary
angle ABC + angle ADC=180
so 93 + angle ADC=180
angle ADC=180-93
angle ADC=87°
now,
as EC is a tangent and CD is a chord
by tangent chord theorem
angle DCE=angle CAD
so angle CAD=35°
now,
in triangle ACD
by angle sum property
angle CDA+angle ADC +angle ACD=180
so angle ACD+35+87=180
angle ACD=180-122
angle ACD=58°
so the measures of required angles are
angle ADC=87°
angle CAD=35°
angle ACD=58°
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