Question

Solve this::

1. P4S3+8O2→P4O10+3SO2

Calculate minimum mass P4S3 is required to produced at least 1 g of each product.

Answer 1

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Answer 2

Answer: The minimum amount of $P_4S_3$ required to produced at least 1 gram of each product is 0.786 grams.

Explanation:

We know that:

Molar mass of $P_4O_{10}$ = 283.886 g/mol

Molar mass of $SO_2$ = 64 g/mol

Molar mass of $P_4S_3$ = 220.093 g/mol

For the given chemical equation:

$P_4S_3+8O_2\rightarrow P_4O_{10}+3SO_2$

By Stoichiometry of the reaction:

If, 283.886 grams of $P_4O_{10}$ is produced by 220.093 grams of $P_4S_3$

Then, 1 gram of $P_4O_{10}$ will be produced by $\frac{220.093}{283.886}\times 1g=0.786g$ of $P_4S_3$

By Stoichiometry of the reaction:

If, 64 grams of $SO_{2}$ is produced by 220.093 grams of $P_4S_3$

Then, 1 gram of $SO_{2}$ will be produced by $\frac{220.093}{64}\times 1g=3.439g$ of $P_4S_3$

Thus, the minimum amount of $P_4S_3$ required to produced at least 1 gram of each product is 0.786 grams.