Question

solve this 100 points​

Answer 1

Answer:

1/2

Step-by-step explanation:

sin2x = 2sin x * cos x

cos π = - 1

sin 90° = 1

~~~~~~~~~~

$cos^{2}x = \frac{1+cos2x}{2}$

$\lim_{x \to \\pi} (\frac{1+cosx}{tan^2 x})$ = lim ( $\frac{2cos^2 (x/2)}{sin^2 x /cos^2 x}$ ) =

lim ( $\frac{cos^2 x*2cos^2 (x/2)}{4sin^2 (x/2) cos^2 (x/2)}$ ) = lim $\frac{cos^2x}{2sin^2 (x/2)}$  

$\frac{cos^2 \pi }{2sin^2 \frac{\pi }{2} }$ = 1/2

Answer 2

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