Question

solve this.........​

Answer 1

Answer:

The formula for the no. of diagonals of a 'n' sided polygon is n(n-3)/2 . It works for triangle (0 diagonals) , quadrilateral (2 diagonals) , pentagon (5 diagonals) and for every another polygon.

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Answer 2

Answer:

9

Step-by-step explanation:

using the geometric concept that : a polygon of n sides has n(n-3)/2 diagonals

then n(n-3)/2 = 27

n(n-3) = 54

n² - 3n -54 = 0

( n + 6  )  ( n -9  ) = 0

n = 9

9 sides