Question

solve this............​

Answer 1

Answer:

√5 (b)

Step-by-step explanation:

use sin(90-x) = cos x and cosec(90-x) = sec x

$\sqrt{ \frac{2 \sin {}^{2} (38) + 2 \cos^2(38) + 3}{ 3\sec {}^{2} (73) - 3 \tan^2(73) - 2} } = \sqrt{ \frac{2 + 3}{3 - 2} } = \sqrt{5}$