Question

solve this !!!......


​

Answer 1

To prove :----

• log(base3)x + 2log(basex)3 = 3

Formula used :------

• log change of base formula that is log(base b)a = (log(base x)a/log(base x)b)
• product of rule of log , that is = log a + log b = log(a × b)
• Expenonant Rule of law .. x.log(a) = log(a)^x

Solution :--------

Step (1) :-----

→ 2.log(x)3 = log(x)3² = log(x)9

Step (2) :-------

[using Change of base formula in Both LHS now we get]

→ log(3)x = [ log(a)x/log(a)3 ]

→ log(x)9 = [ log(a)9/log(a)x ]

Step (3) :-----------

using both as product law we get,

→ log(3)x + log(x)9

→ [ log(a)x/log(a)3 ] × [ log(a)9/log(a)x ]

→ log(a)9/log(a)3

Step (4) :-----------

Again using Exponent Formula in Numerator we get,

→ 3log(a)3/log(a)3

→ 3 = RHS

(Hence Proved)

(Hope it Helps you)

#BAL

Answer 2

Step-by-step explanation:

please ive me thanks and follow me I will follow