Question

solve this..+++++//////////////​

Answer 1

${}{ \huge{ \underline{ \red{ |Solution>| }}}}$

Here, the maximum class frequency is 20, and the class corresponding to this frequency is 40 – 50.

So, the modal class is 40 – 50.

______________________________________

Now, modal class = 40 – 50, lower limit (l) of modal class = 40, class size(h) = 10

frequency (f1) of the modal class = 20

frequency (f0) of class preceding the modal class = 12

frequency (f2) of class succeeding the modal class = 11

==============================

Now, let us substitute these values in the formula,

Mode

$= l + (\frac{f1 - f0}{2f1 - f0 - f2} ) \times h$

$= 40 + ( \frac{20 - 12}{2 \times 20 - 12 - 11} ) \times 10$

$= 40 + \frac{8}{17} \times 10$

$= 40 + 4.7 \\ = 44.7$