Question

-_- SOLVE THIS ~-_-​

Answer 1

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(A) Clearly , C1 , C2 and C3 are connected in series combination

Thus ,

1/C' = 1/10 + 1/10 + 1/10

1/C' = 3/10

C' = 10/3 micro farad

The capacitance C' form a parrallel combination with C4

Thus ,

C" = 10/3 + 10

C" = (10 + 30)/3

C" = 40/3

C" = 13.3

C" = 13.3 × (10)^--6 farad

Hence , the equivalent capacitance is 13.3 × (10)^-6 farad

(B) Clearly , the charge on a C1 , C2 and C3 is same ,

Thus ,

Q' = 500 × (10/3)

Q' = (5/3) × (10)³

Q' = 1.7 × (10)³ micro C

In term of SI unit ,

Q' = 1.7 × (10)³ × (10)^-6

Q' = 1.7 × (10)^-3 C

Hence , the charge on a C1 , C2 and C3 is 1.7 × (10)^-3 C

Now , the charge on a C4 is

10 = Q''/500

Q'' = 500 × 10

Q'' = 5 × (10)³ micro C

In term of SI unit ,

Q'' = 5 × (10)³ × (10)^-6

Q'' = 5 × (10)^-3 C

Hence , the charge on a C4 is 5 × (10)^-3 C

Answer 2

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