Math, asked by nusrat75, 1 year ago

solve this
2+2-(4+2)×(32÷2+8)-20​

Answers

Answered by utsavkumar12362
0

Answer:

2+2-(4+2)×(32÷2+8)-20

4-4-2×16+8-20

-2×16-12

-32-12

-44

Answered by nisha382
4

Answer:

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2+2-(4+2)×(32÷2+8)-20

=2+2-(4+2)×(16+8)-20[using BODMAS]

=4-6×(24-20)

=(-2)×4

=(-8)

Step-by-step explanation:

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