Question

solve this ..........​

Answer 1

Height of tap = 5m and (g) = 10m/sec  

2

 

For the first drop, 5=ut+gt  

2

 

=(0×t)+×10t  

2v

=5t  

2

 or t  

2

=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)  

2

=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m

Answer 2

Answer:

Distance of the second drop above the ground

=5−1.25=3.75m

Step-by-step explanation: