Question

solve this ..........​

Answer 1

Answer:

Step-by-step explanation:

We have

v

′

=

v

−

v

0

​

​

(1)

From the vector diagram [of equation (1)] and using properties of triangle

v

′

=

v

0

2

​

+v

2

+2v

0

​

vcosφ

​

=39.7km/h (2)

and

sin(π−φ)

v

′

​

=

sinθ

v

​

or, sinθ=

v

′

vsinφ

​

or θ=sin

−1

(

v

′

vsinφ

​

)

Using (2) and putting the values of v and d

θ=19.1

∘

Answer 2

Answer:

Refer to the attachment