Question

solve this 3(2y-3)-5 (y-1)​

Answer 1

Answer:

How to solve your question

Your question is

3(2−3)−5(−1)

3(2y-3)-5(y-1)3(2y−3)−5(y−1)

Simplify

1

Distribute

3(2−3)−5(−1)

{\color{#c92786}{3(2y-3)}}-5(y-1)3(2y−3)−5(y−1)

6−9−5(−1)

{\color{#c92786}{6y-9}}-5(y-1)6y−9−5(y−1)

2

Distribute

6−9−5(−1)

6y-9{\color{#c92786}{-5(y-1)}}6y−9−5(y−1)

6−9−5+5

6y-9{\color{#c92786}{-5y+5}}6y−9−5y+5

3

Add the numbers

6−9−5+5

6y{\color{#c92786}{-9}}-5y+{\color{#c92786}{5}}6y−9−5y+5

6−4−5

6y{\color{#c92786}{-4}}-5y6y−4−5y

4

Combine like terms

6−4−5

{\color{#c92786}{6y}}-4{\color{#c92786}{-5y}}6y−4−5y

1−4

{\color{#c92786}{1y}}-41y−4

5

Multiply by 1

1−4

1y-41y−4

−4

y-4y−4

Solution

−4

Step-by-step explanation:

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Answer 2

Answer...

$\tt3(2y - 3) - 5(y - 1) \\ \\ \tt = 6y - 9 - 5y + 5 \\ \\ \tt = 6y - 4 - 5y \\ \\ \tt = y - 4$