Question

solve this .............

Answer 1

find this solution. ........

Answer 2

hey here is your ans
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x-->3
x approaches to 3 then x = 3
now,
$= \frac{{x}^{3} - 7 {x}^{2} + 15x - 9 }{ {x}^{4} - 5 {x}^{3} + 27x - 27 } \\ \\ = \frac{{3}^{3} - 7 \times {3}^{2} + 15 \times 3 - 9 }{ {3}^{4} - 5 \times {3}^{3} + 27 \times 3- 27 } \\ \\ = \frac{27 - 63 + 45 - 9}{91 - 135 + 91 - 27} \\ \\ = \frac{0}{20} \\ \\ = 0$
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