solve this...................
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In Triangle ABD and triangle CDB
AB = DC ( Given)
BD = DB ( Common)
<ABD = <CDB ( alt. Int. Angles)
So,
Triangle ABD is congurent to triangle CDB
[ SAS criteria]
=> AD = CB
And, <ADB = <CBD [ CPCT]
=> AD || CB
Hence,
AD and CB are equal and Parallel.
Hence Proved.
AB = DC ( Given)
BD = DB ( Common)
<ABD = <CDB ( alt. Int. Angles)
So,
Triangle ABD is congurent to triangle CDB
[ SAS criteria]
=> AD = CB
And, <ADB = <CBD [ CPCT]
=> AD || CB
Hence,
AD and CB are equal and Parallel.
Hence Proved.
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