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u=-30cm
f=-15cm
v=1/f+1/u
1/v=1/10
v=10
m=v/u=-1/3
Therefore
Position:between f and P in front of mirror
Nature:Real
Inverted
Magnification: diminished
f=-15cm
v=1/f+1/u
1/v=1/10
v=10
m=v/u=-1/3
Therefore
Position:between f and P in front of mirror
Nature:Real
Inverted
Magnification: diminished
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