solve this 4x2-4x+1=0
find the solution of this equation
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Answered by
58
Hey !!
4x² - 4x + 1 = 0
4x² - 2x - 2x + 1 [✓using spliting method of quadratic equation ]
=> 2x ( 2x - 1 ) -1 (2x - 1 ) = 0
=>( 2x - 1 ) = 0
x = 1/2 1st solution
2x -1 = 0
x = 1/2 2nd solution
we saw both zeroes are same of this equation so It have real & equal roots
*********************************
Hope it helps you !!!
@Rajukumar111
4x² - 4x + 1 = 0
4x² - 2x - 2x + 1 [✓using spliting method of quadratic equation ]
=> 2x ( 2x - 1 ) -1 (2x - 1 ) = 0
=>( 2x - 1 ) = 0
x = 1/2 1st solution
2x -1 = 0
x = 1/2 2nd solution
we saw both zeroes are same of this equation so It have real & equal roots
*********************************
Hope it helps you !!!
@Rajukumar111
Answered by
24
here is your answer
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