Question

solve this 5t³-20t5t³-20t if you are algebra genius​

Answer 1

$Given \:5t^{3} - 20t$

$= 5t(t^{2} - 4 )$

$= 5t(t^{2} - 2^{2} )$

/* By algebraic identity */

$\boxed{ \pink{ a^{2} - b^{2} = ( a + b )( a - b ) }}$

$= 5t( t + 2 ) ( t-2)$

Therefore.,

$\red{ Factors \: of \:5t^{3} - 20t}$

$\green { = 5t( t + 2 ) ( t-2)}$

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Answer 2

${\tt{\purple{\underline{\underline{\huge{Answer:}}}}}}$

$\large{Given}\\ \:5t^{3} - 20t$

$\sf\implies 5t(t^{2} - 4 )$

$\sf\implies 5t(t^{2} - 2^{2} )$

$\boxed{ a^{2} - b^{2} = ( a + b )( a - b ) }$

$= 5t( t + 2 ) ( t-2)$

$Factors \: of \:5t^{3} - 20t$

$\sf\implies 5t( t + 2 ) ( t-2)$

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