solve this 67 number questions
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Remember that secx=1cosx
So
sec330º=1cos(330º)
Remember that cos(a−b)=cos(a)cos(b)+sin(a)sin(b) and that 330º=360º−30º, so
cos(330º)=cos(360º−30º)=cos(360º)cos(30º)+sin(360º)sin(30º)
The cosine, sine, tangent and secant of 360º equal the cosine, sine, tangent and secant of 0º respectively. We know that sin0º is 0, and that cos0º=1 so
cos(330º)=1⋅cos(30º)+0⋅sin(30º)
cos(330º)=√32
So
sec(330º)=2√3
Rationalizing,
sec(330º)=2√33
Pls at least leave a thanks
So
sec330º=1cos(330º)
Remember that cos(a−b)=cos(a)cos(b)+sin(a)sin(b) and that 330º=360º−30º, so
cos(330º)=cos(360º−30º)=cos(360º)cos(30º)+sin(360º)sin(30º)
The cosine, sine, tangent and secant of 360º equal the cosine, sine, tangent and secant of 0º respectively. We know that sin0º is 0, and that cos0º=1 so
cos(330º)=1⋅cos(30º)+0⋅sin(30º)
cos(330º)=√32
So
sec(330º)=2√3
Rationalizing,
sec(330º)=2√33
Pls at least leave a thanks
gourangamandal1974:
cheater
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2
The value of sec 330 is 2 root 3 .
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