Question

find two integers , such that thier sum is -11 and product is -80 ​

Answer 1

Hope this helps ☺️☺️...

Answer 2

Let the two integers be x and y.

$x + y = ( - 11) - - - - - - - 1\\ xy = ( - 80) - - - - - - - - 2$

From eq. 1,

$x = - 11 - y$

Putting this in eq.2,

$\: \: \: \: \: \: ( - 11 - y)y = ( - 80) \\ = > - 11y - {y}^{2} = - 80 \\ = > {y}^{2} + 11y - 80 = 0 \\ = > {y}^{2} + 16y - 5y - 80 = 0 \\ = > y(y + 16) - 5(y + 16) = 0 \\ = > (y + 16)(y - 5) = 0 \\ = > y = ( - 16) \: \: and \: \: (5).$

By putting this value of y in eq.2,

If

$y = ( - 16) \: \: then \: \: x = 5 \\ y = 5 \: \: then \: \: x = ( - 16).$

Hope this will help you. 

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